16.2. Selecting an entity

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This is probably the most common form of query.
The application wants to select entity instances.

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<div class="title">Example 409. Selecting the root entity</div>
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<pre class="prettyprint highlight">`CriteriaBuilder builder = entityManager.getCriteriaBuilder();

CriteriaQuery&lt;Person&gt; criteria = builder.createQuery( Person.class );
Root&lt;Person&gt; root = criteria.from( Person.class );
criteria.select( root );
criteria.where( builder.equal( root.get( Person_.name ), "John Doe" ) );

List&lt;Person&gt; persons = entityManager.createQuery( criteria ).getResultList();`</pre>
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The example uses `createQuery()` passing in the `Person` class reference as the results of the query will be `Person` objects.

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The call to the `CriteriaQuery#select` method in this example is unnecessary because _root_ will be the implied selection since we have only a single query root.
It was done here only for completeness of an example.

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The `Person_.name` reference is an example of the static form of JPA Metamodel reference.
We will use that form exclusively in this chapter.
See the documentation for the [Hibernate JPA Metamodel Generator](https://docs.jboss.org/hibernate/orm/5.2/topical/html/metamodelgen/MetamodelGenerator.html) for additional details on the JPA static Metamodel.

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